Area moment of inertia equation of cross8/17/2023 This happens because more mass is distributed farther from the axis of rotation. We would expect the moment of inertia to be smaller about an axis through the center of mass than the endpoint axis, just as it was for the barbell example at the start of this section. Next, we calculate the moment of inertia for the same uniform thin rod but with a different axis choice so we can compare the results. In the case with the axis in the center of the barbell, each of the two masses m is a distance R away from the axis, giving a moment of inertia of In this case, the summation over the masses is simple because the two masses at the end of the barbell can be approximated as point masses, and the sum therefore has only two terms. To see this, let’s take a simple example of two masses at the end of a massless (negligibly small mass) rod ( Figure 10.23) and calculate the moment of inertia about two different axes. Because r is the distance to the axis of rotation from each piece of mass that makes up the object, the moment of inertia for any object depends on the chosen axis. We defined the moment of inertia I of an object to be I = ∑ i m i r i 2 I = ∑ i m i r i 2 for all the point masses that make up the object. This section is very useful for seeing how to apply a general equation to complex objects (a skill that is critical for more advanced physics and engineering courses). In this section, we show how to calculate the moment of inertia for several standard types of objects, as well as how to use known moments of inertia to find the moment of inertia for a shifted axis or for a compound object. In the preceding section, we defined the moment of inertia but did not show how to calculate it.
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